WebSolution-1: Using collection module. In this solution, we will reads a list of words from the user, counts the frequency of each word in the list, and prints the number of unique … WebCalculate the total score of the list of words.

HackerRank Matching Word & Non-Word Character Solution

WebCode your solution in our custom editor or code in your own environment and upload your solution as a file. 4 of 6; Test your code You can compile your code and test it for errors and accuracy before submitting. 5 of 6; Submit to see results When you're ready, submit your solution! Remember, you can go back and refine your code anytime. 6 of 6 WebJan 17, 2024 · Fast anagrams checker algorithm (HackerRank) Given two arrays of strings, for every string in list (query), determine how many anagrams of it are in the other list (dictionary). It should return an array of integers. The answer would be [2, 2, 0, 3, 1] since query [0] ('a') has 2 anagrams in dictionary: 'a' and 'a' and so on... god of war eula

The Time in Words HackerRank

WebNote: This problem (The Time in Words) is generated by HackerRank but the solution is provided by CodingBroz. This tutorial is only for Educational and Learning purpose. Webcomputer-science es6 algorithms datastructures leetcode solutions cracking-the-coding-interview topcoder software-engineering leetcode-solutions problem-solving es5 … WebSolution-2: swapcase () method. Now, let us use the swapcase () method to solve the given problem: def swap_case ( s ): return s.swapcase () if __name__ == '__main__' : s = input () result = swap_case (s) print (result) This code defines a function called " swap_case " which takes a string as input and uses the built-in string method " swapcase ... god of war estreia